A wireframe is bent into a circle of diameter 56 is reshaped as a rhombus. What is the length of the side of the resulting rhombus? (assume π =  
22
7
 )


Answer:

44

Step by Step Explanation:
  1. A wireframe of some length was first bent into a circle and then reshaped as a rhombus:
    Wire Circle Rhombus
  2. Let us first find the length of the wireframe. We know that the total length of the boundary of a circle is called its circumference and is given by:
    Circumference = 2πr, where r is the radius of the circle.
    Since the circle is formed by the wireframe, the length of the wireframe = 2πr
    = 2 ×  
    22
    7
      × 28 [It is given that the radius of the circle is 56/2 = 28 and π =  
    22
    7
     ]

    = 176
  3. Now, we know that the same wire frame with length 176 is reshaped as a rhombus. A rhombus has 4 sides and all sides are equal. This means the length of a side of the rhombus will be 176 divided by 4. That is:
     
    176
    4
     
    = 44
  4. Thus the length of the side of the resulting rhombus is 44.

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