Construct a right triangle whose base is 17 cm17 cm17 cm and sum of its hypotenuse and another side is 23 cm23 cm23 cm.


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Answer:

C B X D A

Step by Step Explanation:
  1. Let ABCABCABC be the required triangle such that BC=17 cm,∠B=90∘BC=17 cm,∠B=90∘BC=17 cm,∠B=90∘ and AC+AB=23 cmAC+AB=23 cmAC+AB=23 cm. Draw a BC=17 cm.BC=17 cm.BC=17 cm. C B
  2. At BBB construct ∠CBX=90∘.∠CBX=90∘.∠CBX=90∘. C B X
  3. From BBB cut off BD=23 cmBD=23 cmBD=23 cm. C B X D
  4. Join CDCDCD and draw perpendicular bisector of CDCDCD intersecting BDBDBD at AAA. C B X D A
  5. Join ACACAC to get the required triangle ABCABCABC. C B X D A

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