### Draw a circle with its two chords $PQ$ and $RS$ such that $PQ$ is not parallel to $RS$. Draw the perpendicular bisector of $PQ$ and $RS$. At what point do they intersect each other? Justify the steps of construction.

Step by Step Explanation:
1.  Draw a circle with any radius and center $O$. O
2.  Draw two chords $PQ$ and $RS$. O PQ RS
3.  With center $P$ and radius more than half of $PQ$, draw arcs on each side of the chord $PQ$. O PQ RS
4.  With center $Q$ and same radius, draw arcs cutting the previous arcs at $A$ and $B$ respectively. O PQ RS B A
5.  Join $AB$. O PQ RS B A
6.  With center $R$ and radius more than half of $RS$, draw arcs on each side of chord $RS$. O PQ RS B A
7.  With center $S$ and same radius, draw arcs cutting the previous arcs at $C$ and $D$ respectively. O PQ RS B A CD
8.  Join $CD.$ $AB$ and $CD$ are the required perpendicular bisector of $PQ$ and $RS$ respectively. O PQ RS B A CD
9. Both perpendicular bisector $AB$ and $CD$ intersect each other at the center of the circle.