If Jeff drives at three fourth of his usual speed, he covers a certain distance in 3 hours more than the time he takes while driving at his usual speed. Find the time taken by him to cover this distance with his usual speed.
Answer:
9 hours
Let us assume that Shweta drives at a usual speed of S km/hr and takes t hours to cover a certain distance.
According to the question,
If, speed =
× S km/hr3 4
Time = t + 3 hoursWe know that the distance travelled in both the cases remains same.
Also, Distance = Speed × Time
So, S × t =
× S × (t + 3)3 4
⇒ St =
S(t + 3)3 4
⇒ St =
St +3 4
S9 4
⇒ St -
St =3 4
S9 4
⇒
St =1 4
S9 4
⇒ t = 9- Thus, the time taken by her to cover the distance with usual speed is 9 hours.