### There are a cylinder and a cone with height, $h$ and radius $r$. There is also a sphere of the same radius. The height, $h$ of the cylinder and the cone is $3$ times the radius, $r$. If $V_1$ is the volume of the cylinder, $V_2$ is the volume of the cone and $V_3$ is the volume of the sphere, write the given volumes in ascending order.

$V_2 < V_3 < V_1$

Step by Step Explanation:
1. Three solid figures have been provided. The volume of all three solid figures is to be compared.
 h r Cylinder h r Cone Sphere
2. It is given that the height, $h$ of the cylinder and the cone $= 3 × r$
The volume of the cylinder, $V_1 = \pi r^2 h = \pi r^2 (3 r) = 3 \pi r^3$
The volume of the cone, $V_2 = \dfrac{ 1 }{ 3 } \pi r^2 h = \dfrac{ 1 }{ 3 } \pi r^2 (3 r) = \pi r^3$
The volume of the sphere, $V_3 = \dfrac{ 4 }{ 3 } \pi r^3 = 1.33 \pi r^3$
3. On comparing the volumes of the three figures, \begin{align} & \pi r^3 < 1.33 \pi r^3 < 3 \pi r^3 \\ \implies & V_2 < V_3 < V_1 \end{align}